Courses βΈ± Algorithms
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Lecture Recording
In-class Quiz Questions
We continue exploring examples and non-examples of matroids.
- Let be a undirected and connected graph. Let be the ground set. A subset is independent if the complementary subgraph of is connected. Consider the example shown in the figure below. Do the highlighted edges form an independent set?
- Yes
- No

Reveal answer
Yes
There are no cycles among the highlighted edges.
- Let be a undirected and connected graph. Let be the ground set. A subset is independent if the complementary subgraph of is connected. Consider the example where the graph G is a star, as shown below. What is the family of independent sets?
- Empty set.
- All singleton edges; i.e, the size of the family is 7 for the example above.
- All subsets of edges belong to the family; i.e, the size of the family is 128 for the example above
- None of the above

Reveal answer
Empty set.
There is no edge whose removal keeps connected.
- Suppose is subset of edges such that is connected. Further, let be a subset of What can you say about ? (Hint: think about in terms of . Is it a subgraph? A supergraph?)
- Also connected.
- May or may not be connected.
- Will not be connected.
- None of the above.
Reveal answer
Also connected
is a supergraph of which was already connected.
- Suppose is a subset of edges such that is connected. Suppose is a subset of edges such that is connected. Further, suppose . What can we say about the number of edges in ? Pick the strongest claim you can make. Hint: since is connected, it must have at least how many edges? Now put two and two together given that .
- at least
- at least
- at least
Reveal answer
at least
A connected graph with exactly one cycle will have at least edges.
- Let be an undirected and connected graph. Let be the ground set. A subset is independent if the complementary subgraph of is connected. Does this collection of independent sets form a matroid? Hint: for the exchange axiom, consider that a graph with at least n edges has a cycle.
- Yes
- No, it violates the first axiom (empty set membership)
- No, it violates the second axiom (heredity)
- No, it violates the third axiom (exchange axiom)
Reveal answer
Yes
- Let be an arbitrary undirected graph. Let be the ground set, and let be the family of all subsets of that form a matching. Does this family form a matroid? (Hint: Consider a path on four vertices and three edges. Can you find two matchings here that may give you some insights on one of the axioms?)
- Yes
- No, it violates the first axiom (empty set membership)
- No, it violates the second axiom (heredity)
- No, it violates the third axiom (exchange axiom)
Reveal answer
No, it violates the third axiom (exchange axiom)
Follow the hint.
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